31:[] 2f:{"title":"Laminated Dough Calculator","cells":[{"id":0,"value":"md`# Laminated Dough Calculator\n\nA little notebook to help me understand the structure of [laminated dough](https://en.wikipedia.org/wiki/Laminated_dough) (used for croissants, danishes, puff pastry etc.) depending on how it's folded (layering dough with butter). [Here's an article](https://www.theculinarypro.com/laminated-dough) with a good summary of the process.`","pinned":false,"hidden":false,"mode":"ojs"},{"id":172,"value":"{\n const height = 200;\n const ctx = DOM.context2d(width, height);\n \n let layers = ({\n 'French': [0, 1, 0],\n 'English': [0, 1, 0, 1, 0],\n 'Book': [0, 1, 0, 0, 1, 0]\n })[folds.lockin];\n\n for (let i = 0; i < folds.letter; i++) layers = layers.concat(layers, layers);\n for (let i = 0; i < folds.single + folds.book * 2; i++) layers = layers.concat(layers);\n \n const h = height / layers.length;\n for (let i = 0; i < layers.length; i++) {\n ctx.fillStyle = layers[i] ? 'yellow' : '#999';\n ctx.fillRect(0, i * h, width, (i + 1) * h);\n }\n return ctx.canvas;\n}","pinned":false,"hidden":false,"mode":"ojs"},{"id":59,"value":"viewof folds = form(html``)","pinned":false,"hidden":false,"mode":"ojs"},{"id":127,"value":"md`\nResulting dough: **${layers} layers** (${(layers - 1) / 2} butter layers & ${(layers - 1) / 2 + 1} dough layers).\n\nA classic French croissant has 55 layers (27 layers of butter), achieved with a French fold followed by 3 letter folds. Less layers will mean a different texture (less tender, more chewy, with more defined layers). Too many layers bring a risk of the butter getting too thin and melting into the dough.\n\nNote that English and book folds for locking in butter produce the same number of layers, but the first leads to an inconsistent layer pattern, because it has a single dough layer between layers of butter, while folding melds two dough layers together.\n`","pinned":false,"hidden":false,"mode":"ojs"},{"id":96,"value":"layers = {\n let n = folds.lockin === 'French' ? 3 : 5;\n for (let i = 0; i < folds.letter; i++) n = 3 * n - 2;\n for (let i = 0; i < folds.single + 2 * folds.book; i++) n = 2 * n - 1;\n return n;\n}","pinned":true,"hidden":false,"mode":"ojs"},{"id":61,"value":"import {form} from '@mbostock/form-input'","pinned":false,"hidden":false,"mode":"ojs"},{"id":253,"value":"html``","pinned":true,"hidden":false,"mode":"ojs"}],"files":"$W31","stdlib":"1","titling":"auto"}